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how to know this code? i think this is binary code
010001010111001001111010011000010010000001010011011000110110000101110010011011000110010101110100
i want to break this code with lua code...
anyone can help me?
Thanks
Sorry if im bad english
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6 replies
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how to know this code? i think this is binary code
010001010111001001111010011000010010000001010011011000110110000101110010011011000110010101110100
i want to break this code with lua code...
anyone can help me?
Thanks
Sorry if im bad english
I can't comprito this.
Edit:
I assume that it is an ASCII encoded string. So 8 bits form a byte and each byte can be translated into a letter using an ASCII table.
edited 1×, last 05.03.13 01:06:09 pm
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yournumber = "010001010111001001111010011000010010000001010011011000110110000101110010011011000110010101110100" -- this is the binary number decoded = tonumber(tostring(yournumber),2)
Assuming that's a number. If it's an encoded string, then you need this function:
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function bintoascii(bin,big) -- set big to true if it's big endian, leave be if it's little endian local str="" if not big then bin=bin:reverse() end local j=1 for i=8,#bin,8 do local ascii=tonumber(bin:sub(j,i),2) str=str..string.char(ascii) j=i+1 end return str end
In your case it is a string, and using the function above with Big Endian mode on we can see that this is "Erza Scarlet".
edited 3×, last 05.03.13 01:21:54 pm
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local bin = "010001010111001001111010011000010010000001010011011000110110000101110010011011000110010101110100";
function bin2text(bin)
return bin:gsub('('..('[01]'):rep(8)..')', function(b) return string.char(tonumber(b, 2)) end);
end
print(bin2text(bin));
You can test it at http://www.lua.org/cgi-bin/demo
- x0rh4x.
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