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CS2D Scripts Round off decimal value

# Round off decimal value

7 replies
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#### Round off decimal value

Ace Howl
User Offline

Hello, currently I'm inactive playing this game (sad much ) but I have a 'thing' that need to be solved.

As stated from the title, I searched for round off, decimal and whole but found none. So, the question is: how to round off decimal value into whole number.

For example, using 'distance between 2 players' code (distance between two points [Pythagoras Theorem thing]) code will return long-ass decimal values (e.g. 3.69420666) most of the instance. That is inconvenient for me during actual gameplay.

Any ideas?

#### Re: Round off decimal value

Starkkz
Moderator Offline

Some people uses
`math.floor(x + 0.5)`
.

#### Re: Round off decimal value

Baloon
GAME BANNED Offline

Use this math. calculation
`math.floor`
or
`math.ceil`

Example:
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```math.floor(6.12314) > 6
math.floor(7.90999) > 7
math.floor(3)          > 3

math.ceil(1.00001) > 2
math.ceil(5.93213) > 6
math.ceil(2)          > 2
```

#### Re: Round off decimal value

Zeik
User Offline

As Starkkz said, use
`math.floor(x + 0.5)`
whether you want to round up if the fractional part of x is greater or equal than 0.5, or whether you want to round down if the fractional part of x is lower than 0.5.
Note that it would only work with positive numbers, as it would be the opposite for negative numbers to work:
`math.floor(x - 0.5)`
.

If you just want to round down no matter what is the fractional part, just use
`math.floor(x)`

#### Re: Round off decimal value

Ace Howl
User Offline

And how does that operation work?
Let's say I've calculated some Pythagoras value and is in fraction.
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```-- As example only
local neardist = (contain-decimal-value)
if txt==("nearest") then
parse("msg2 "..id.." "..neardist)
end
```

Where should I settle the job?

#### Re: Round off decimal value

Baloon
GAME BANNED Offline

If that's you want (distance between- ) i can't do that, in my way, that needs much math codes like math.rad, math.cos, math.tan, etc.

#### Re: Round off decimal value

Rainoth
Moderator Offline

@ Ace Howl: So what don't you get? It rounds the number. You can't add fractions in your head and see how it works..? I don't get you.

Here's a few example of what
`math.floor(x + 0.5)`
does when x is:
0.51234 1
0.498765 0
420.69 421
419.50 420
777.321 777

Just take whatever number and whatever fraction it has after you add 0.5 you take away.

@ Baloon: As Ace Howl said, the only thing you need to get distance is basic understanding of pythagorean theorem. They teach those in 5th-6th grade I guess, maybe earlier.

#### Re: Round off decimal value

EngiN33R
Moderator Offline

On its own, the function
`math.floor(a)`
finds such integer n (n ∈ Z) that n ≤ a. Thus, for any positive number it will return that number without its fractional part - 0.3 becomes 0, 1.8 becomes 1, 17.5 becomes 17 etc. For any negative number, it will return the number before it, so -1.3 becomes -2, -4.75 becomes -5 etc.

The trick behind
`math.floor(a+0.5)`
is that any number with a fractional part smaller than 0.5 retains the same integer part (0.3 + 0.5 is 0.8, the integer part is still 0), whereas for any number with a fractional part larger than or equal to 0.5 the integer part will increase by 1, and the fractional part will be removed (0.75 + 0.5 is 1.25, or 1 without the fractional part thanks to flooring).

Hence, you should use this whenever you want your value to be rounded. That depends entirely on you. In your sample code, you can do the following:
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```local neardist = math.floor(math.sqrt((x-x2)^2+(y-y2)^2)+0.5)
if (txt == "nearest") then
msg2(id, neardist)
end
```
Alternatively, if you want to store the exact distance and only display it in a user-friendly way, you can do it like this:
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```local neardist = math.sqrt((x-x2)^2+(y-y2)^2)
if (txt == "nearest") then
msg2(id, math.floor(neardist+0.5))
end
```
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