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depending on dir
example if the direction is 15 and current x and y is 10
then
four_dir[1] = {x=10,y=9}
four_dir[2] = {x=11,y=10}
four_dir[3] = {x=9,y=10}
four_dir[4] = {x=10,y=11}
its hard to explain, but i hope you understand understand...
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CS2D
Scripts 4 directions sort
4 directions sort
4 Antworten
1 
depending on dir
example if the direction is 15 and current x and y is 10
then
four_dir[1] = {x=10,y=9}
four_dir[2] = {x=11,y=10}
four_dir[3] = {x=9,y=10}
four_dir[4] = {x=10,y=11}
its hard to explain, but i hope you understand understand...
Anyways, I can try:
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function sort_pos(x,y)
local t = {}
for k,v in pairs(player(0,"tableliving")) do
table.insert(t,{player(v,"x"), player(v,"y")})
end
table.sort(t,
function(a,b)
return math.sqrt(((a[1]-x)^2+(a[2]-y)^2) < ((b[1]-x)^2+(b[2]-y)^2))
)
return t
end
Hm could...
You see the parameters should be
X,y,direction
Then it should give the table, from x,y in direction sorted, can you fix that? Thx
1× editiert, zuletzt 23.06.11 00:28:46
And you still haven't explained me what you mean by direction.
Ok so player is on a tile x y, theres a total of 8 tilrs around, now skip the tiles diagonnally , now we got 4 tiles
Lets say player moves in a direction, he would walk on 1 of these tiles(in most case)
The tile is easy to find, but lets say player moves in a direction, however the tile is already occupyed, wich of the oyher 3 tiles would then be closest to turn towards, third should be opposite to this, and fourth opposite to first tile
Get it?
I mean if the direction is 15, closest direction(/90)
Is up
Second closest would be right
Third closest would be left and fourt is down
ok listen, lets say im on tile 10x, and 15y
having 15 angle (rot)
first tile infron of me would be the 10x, 14y
second closest would be 11x 15 y
third closest would be 9x 15 y
and the fourth closest would be 10x 16 y
edit:
solved it myself
heres the code
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function four_dir (dir)
dir_fixed = round(dir/90)*90
x_add = {}
y_add = {}
x_add[1] = round(math.cos(math.rad((dir_fixed) - 90)))
y_add[1] = round(math.sin(math.rad((dir_fixed) - 90)))
if dir < dir_fixed then
dir_fixed = math.floor(dir/90)*90
else
dir_fixed = math.ceil(dir/90)*90
end
x_add[2] = round(math.cos(math.rad((dir_fixed) - 90)))
y_add[2] = round(math.sin(math.rad((dir_fixed) - 90)))
x_add[3] = -x_add[2]
y_add[3] = -y_add[2]
x_add[4] = -x_add[1]
y_add[4] = -y_add[1]
end
2× editiert, zuletzt 23.06.11 16:13:58
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